A gold wire 5.96 m long and of diameter 0.860 mm carries a current of 1.26 A.
Find the resistance of this wire.
Find the potential difference between its ends.
Find the resistance of this wire.
Find the potential difference between its ends.
-
R = ρ*A/L
R = ρ*(pi*r^2)/L
R = (2.24*10^-8)*(pi*(0.0086/2)^2)/5.96 ohms
V = R*I
V = R*1.26 volts
R = ρ*(pi*r^2)/L
R = (2.24*10^-8)*(pi*(0.0086/2)^2)/5.96 ohms
V = R*I
V = R*1.26 volts