Find the RESISTANCE of this wire
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Find the RESISTANCE of this wire

[From: ] [author: ] [Date: 12-02-27] [Hit: ]
0086/2)^2)/5.V = R*1.......
A gold wire 5.96 m long and of diameter 0.860 mm carries a current of 1.26 A.
Find the resistance of this wire.
Find the potential difference between its ends.

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R = ρ*A/L
R = ρ*(pi*r^2)/L
R = (2.24*10^-8)*(pi*(0.0086/2)^2)/5.96 ohms

V = R*I
V = R*1.26 volts
1
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