What is the weight in water, if a lead-weight with a density of 5 g/cm^3 and a volume of 2 cm^3 is inside a pool of water?
-
The weight in water is V (ρ – σ) *g where ρ is density of the object and σ is the density of water
V( ρ – σ) *g = 2*( 5 – 1)* 980 = 7840 dyne = 0.0784 N
=====================================
V( ρ – σ) *g = 2*( 5 – 1)* 980 = 7840 dyne = 0.0784 N
=====================================