A 4.74 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=10.2 N at an angle θ= 23.0° above the horizontal, as shown.
What is the speed of the block 3.70 seconds after it starts moving?
What is the speed of the block 3.70 seconds after it starts moving?
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Horizontal force = F cos θ = 10.2 cos 23 = 9.39 N
Acceleration = force / mass = 9.39 / 4.74 = 1.98 m/s^2
v = at = 1.98*3.7 = 7.33 m /s
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Acceleration = force / mass = 9.39 / 4.74 = 1.98 m/s^2
v = at = 1.98*3.7 = 7.33 m /s
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