Speed of block question!
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Speed of block question!

[From: ] [author: ] [Date: 12-02-12] [Hit: ]
Acceleration = force / mass = 9.39 / 4.74 = 1.v = at = 1.98*3.7 = 7.......
A 4.74 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=10.2 N at an angle θ= 23.0° above the horizontal, as shown.

What is the speed of the block 3.70 seconds after it starts moving?

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Horizontal force = F cos θ = 10.2 cos 23 = 9.39 N

Acceleration = force / mass = 9.39 / 4.74 = 1.98 m/s^2

v = at = 1.98*3.7 = 7.33 m /s
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