You are given the y-coordinate to be y = sqrt{3}/2 of a point P on the unit circle that lies in quadrant 2. Find the x-coordinate of point P.
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x is negative in Quadrant 2, so
x = -√(1² - (√3/2)²) = -1/2.
The "1²" in the square root comes from the fact that P lies on the unit circle (r = 1).
x = -√(1² - (√3/2)²) = -1/2.
The "1²" in the square root comes from the fact that P lies on the unit circle (r = 1).