Physics help with two questions
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Physics help with two questions

[From: ] [author: ] [Date: 12-01-05] [Hit: ]
when you said 6.6.6 x 10^7 ?6.6x10^7 / 19000 = 3473.or 57.......
A student weighing 734 N climbs at constant
speed to the top of an 12 m vertical rope in
15 s.
What is the average power expended by the
student to overcome gravity?
Answer in units of W
002 10.0 points
How long does it take a 19 kW steam engine
to do 6.6 × 107 J of work?
Answer in units of s
If poissible put at least 3 decmil places

-
question 1

Find Work done then divide by time

F x D = E

P = E / T


734 x 12 =8808J You can use 734 because there are no net forces due to constant speed

8808/15 = 587.200w

Question 2


when you said 6.6 x107 j did you mean

6.6 x 10^7 ?


well Power = Total energy divided by time

therefore

6.6x10^7 / 19000 = 3473.684 seconds

or 57.895 minutes
1
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