One satellite is in orbit at height of 850.0 km above the earths surface. How long in minutes does it take t

One satellite is in orbit at height of 850.0 km above the earths surface. How long in minutes does it take this satellite to orbit earth?

dont forget to rate please!, also tell me where i lack since this is my first answering

iam assuming t as timeperiod for satellite to complete one revolution around earth

since the satellite revolves at a heght h

the gravitational force provides the necessary centripetal force

thus

GMm/d^2 = mv^2/d

GM/d=v^2 here d= radius of earth + the height of satellite from surface of earth

GM/R+h =v^2 sub values get the value of velocity then

use 2*pie*d= v *t ( circumference of the orbiatl path)

so u get teh value of t anywyas are u a jee aspirant? iam so pls dont forget to vote that will motivate me :)

GM for earth = 4e14 Nm²/ kg

R = (6371+ 800)*1e3 = 7.171e6 m

V = √ [GM/r] = √ [4e14/ 7.171e6]

T = 2πR/ V = 2π * (7.171e6) ^1.5 / √ 4e14

T = 6033 s = 100.5 minutes

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