Magnetism physics problem
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Magnetism physics problem

[From: ] [author: ] [Date: 11-12-15] [Hit: ]
Since you block such examinations (as I do), its means listing and searching by eye and that isnt so much fun anymore.......

4.    m•v² / r = q•B•v

Make sense? Well, at least the units work out so far and I think I'm on the right track.

Just a side note here. Dividing both sides by v and m gives:

5.    v / r = q•B / m

Note that since q, B, and m are known without regard to the velocity v the right side represents a constant. So v/r must always be a constant under these circumstances and it follows that if v increases, so must r in just the same proportion.

Anyway, moving on and solving (5) for r and substituting in (3) for v we get:

6.    r = m•v / q•B = (1/B) • √[ 2•V•m / q ]

Which gives:

    (1/1.6 tesla) • √[ ( 2 • 10x10³ volts • 3.3x10^-27 kg ) / ( 1.6x10^-19 Coulomb ) ]
    or 1.269381 centimeters

So about 1.27cm is what I get.

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I could if I knew what they were. Since you block such examinations (as I do), it's means listing and searching by eye and that isn't so much fun anymore.

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