Gold can be recovered from sea water by reacting the water with zinc, which is refined from zinc oxide. The zinc displaces the gold in the water. What mass of gold can be recovered if 5.00 g of ZnO and an excess of sea water are available?
2 ZnO(s) + C(s) 2 Zn(s) + CO2(g)
2 Au3+(aq) + 3 Zn(s) 3 Zn2+(aq) + 2 Au(s)
2 ZnO(s) + C(s) 2 Zn(s) + CO2(g)
2 Au3+(aq) + 3 Zn(s) 3 Zn2+(aq) + 2 Au(s)
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how are you at dimensional analysis?
5.00g ZnO x (1 mole ZnO / 81.38g ZnO) x (2 moles Zn / 2 moles ZnO) x (2 moles Au / 3 moles Zn) x (197.0g Au / mole Au) = 8.07g Au
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do you understand that?
5.00g ZnO x (1 mole ZnO / 81.38g ZnO) x (2 moles Zn / 2 moles ZnO) x (2 moles Au / 3 moles Zn) x (197.0g Au / mole Au) = 8.07g Au
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do you understand that?