(1/4) A ball is thrown horizontally from the top of a building 45.9m high. The ball strikes the ground at a point 121m from the base of the building. The acceleration of gravity is a 9.8m/s^2. Find the time the ball is in motion. (FOUND THE ANSWER: 3.060612184 seconds)
(2/4) Find the initial velocity of the ball. Answer in units of s.
(3/4) Find the x component of its velocity just before it strikes the ground. Answer in units of m/s.
(4/4) Find the y component of its velocity just before it strikes the ground. Answer in units of m/s.
(2/4) Find the initial velocity of the ball. Answer in units of s.
(3/4) Find the x component of its velocity just before it strikes the ground. Answer in units of m/s.
(4/4) Find the y component of its velocity just before it strikes the ground. Answer in units of m/s.
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1. 45.9 = (.5)(9.81)(t^2) so t=3.06 s
2. 121 / 3.06 = 39.22 m/s
3. 39.22 m/s same final as initial
4. v = (9.81)(3.06) = 30.02 m/s
2. 121 / 3.06 = 39.22 m/s
3. 39.22 m/s same final as initial
4. v = (9.81)(3.06) = 30.02 m/s