Physics Question Regarding Acceleration, Tension.
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Physics Question Regarding Acceleration, Tension.

[From: ] [author: ] [Date: 11-05-24] [Hit: ]
Thanks. (:-1. Obviously,(3 kg - 2 kg) *9.81 m/s^2 = 9.The systems total inertial mass is 10 kg.......
This is the setup.

http://imageshack.us/photo/my-images/155…

Given this setup, can someone help me
a) Find the acceleration and the tension in the string, assuming that the setup is frictionless?
b) How about if there will be friction and the coefficient of friction is 0.4?

I'd really appreciate it if there will be explanation. Thanks. (:

-
1. Obviously, the net force moving the system to the left side is

(3 kg - 2 kg) *9.81 m/s^2 = 9.81 N

The system's total inertial mass is 10 kg. Hence the system as a whole will accelerate with:

a = F/m = 9.81 N / 10 kg = 0.981 m/s^2

From this we can obtain all the tensions:

left side string:

3kg * 9.81 m/s^2 - T1 = 3 kg * 0.981 m/s^2 => T1 = 26.487 N

right side string:

T1 - T2 = 5 kg * 0.981 m/s^2 => T2 = 26.5N - 4.905N = 21.58 N

check with right hanging block:

2 kg * 0.981 m/s^2 = 1.962N as a net force on the 2kg block.

This checks out with T2 - m g = 1.962 N

b)
The net force on the entire system is now 9.81 N - 5kg * 9.81m/s^2 * 0.4 which is less than zero, signifying that the blocks will not move...
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