Here's the problem:
In the series circuit (there's a pic that I obviously can't draw), if the current through R1 is 1.5 A, what is the current through R2?
I have the equation I=V/R, but I don't think that I have enough information to solve the problem. Could this be right?
In the series circuit (there's a pic that I obviously can't draw), if the current through R1 is 1.5 A, what is the current through R2?
I have the equation I=V/R, but I don't think that I have enough information to solve the problem. Could this be right?
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In a SERIES circuit the current must be that same at all points.
So the current through R2 is identical to that through R1
ie it is 1.5A
V=IR is not needed in this problem.
So the current through R2 is identical to that through R1
ie it is 1.5A
V=IR is not needed in this problem.
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for series circuits the equivalent resistance is R=R1+R2. .
Now to determine R1 or R2, you should be given the value of I and V
Then with R=V/I, find out the R, the equivalent resistance,
Then simply input it in the 1st formula and you'll get either of the resistors if one is given. .
But if I and V not given then the problem can't be solved.
But here's a trick too. . For series circuits the current is same through both of the resistors, so if the problem regards only current throug the 2nd resistor then you simply put the main current I as your answer that is 1.5 amp
Now to determine R1 or R2, you should be given the value of I and V
Then with R=V/I, find out the R, the equivalent resistance,
Then simply input it in the 1st formula and you'll get either of the resistors if one is given. .
But if I and V not given then the problem can't be solved.
But here's a trick too. . For series circuits the current is same through both of the resistors, so if the problem regards only current throug the 2nd resistor then you simply put the main current I as your answer that is 1.5 amp
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In a series circuit, all the current through R1 is also through R2.
You don't need the value of R2. The current is the same.
You don't need the value of R2. The current is the same.