Pythagorean theorem with variables
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Pythagorean theorem with variables

[From: ] [author: ] [Date: 11-05-12] [Hit: ]
......
ok so this problem is based on the a^2+ b^2 is c^2 Please help me solve it and find n
And explain in steps how you got it

(n)^2 +(n+3)^2= (n+6)^2

-
n^2 + n^2 + 6*n + 9 - n^2 - 12*n - 36 = 0

n^2 - 6*n - 27 = 0

(n + 3)*(n - 9) = 0

Answer: n = 9
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keywords: variables,theorem,Pythagorean,with,Pythagorean theorem with variables
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