311, sq-root = t = 0.5577 secsgt = v = 5.465 m/slets say it takes 0.1 sec to stop10 grams = 0.01 kg(0.......
I think you are confusing "force" here with other things. A stone dropped from 500 ft would have a MUCH greater speed when it hit the ground than one dropped from 5 ft.
That's because the 500 ft stone spends much more time in the air, so it has much more time to accelerate (speed up) due to the earth's gravitational pull.
And since energy and momentum both depend on speed, the 500 ft stone will have MUCH more energy and momentum than the 5 ft stone.
And it's energy and momentum you "feel" when a falling stone strikes your hand! That's why a stone falling from 500 ft would hurt much more than one falling from 5 ft (even though the weigh the same).
Hope this helps.
It's a common mistake with people new to physics.
change in momentum / time = force acting
momentum = mass x velocity
ignoring air resistance
5 feet = 1.524 m
1.524/4.9 = t^2 = 0.311, sq-root = t = 0.5577 secs
gt = v = 5.465 m/s
lets say it takes 0.1 sec to stop
10 grams = 0.01 kg
(0.01 x 5.465)/0.1 = 0.5465 N force
500 feet = 152.4 m
152.4/4.9 = 31.1, sq-root = t = 5.577 secs
gt = 9.8 x 5.577 = v = 54.654 m/s
lets say it stops in 0.01 secs
(0.01 x 54.654)/0.01 = 54.654 N
there is slight deviation in the gravity. at the center of the earth and out of earths atmosphere the gravity is zero.so when we go nearer to earths surface(crust) the gravity increases so there eill be a difference in the force too.
