Work and power please help!

A person opens a door by applying a 10-N force perpendicular to it at a distance 0.70m from the hinges. The door is pushed wide open (to 120degrees) in 2.4s.

How much work was done?

What was the average power delivered?

The force is 10 N. The distance moved parallel to the force is 2πr*(120/360) = 2π(.7)(1/3) = 1.466 m
Then the work is given by W = F * d = 10 * 1.466 = 14.66 Joules
Power = W/t = 14.66/2.4 = 6.11 J/s = 6.11 Watts

W = torque x angle(in radians)
torque = F x r
r = length of the lever arm (0.70m)
angle = angle in degrees x 180 degrees/pi
So, W = 7Nm x 40
W = 280 Joules

P = change in work/change in time
so, P = 280/2.4
P = 116.7 Watts

Note that your answer may differ depending on how you want to round it. :)