im getting really muddled with electricity...as always! :(
my textbook says that in parallel circuits, bulbs are brighter because the voltage isnt shared
but if power is voltage x current, how comes the current dividing in a parallel circuit doesnt cancel out that effect?
sorry dont think thats very clear ^ ...
thanks!
my textbook says that in parallel circuits, bulbs are brighter because the voltage isnt shared
but if power is voltage x current, how comes the current dividing in a parallel circuit doesnt cancel out that effect?
sorry dont think thats very clear ^ ...
thanks!
-
im getting really muddled with electricity...as always! :(
my textbook says that in parallel circuits, bulbs are brighter because the voltage isnt shared but if power is voltage x current, how comes the current dividing in a parallel circuit doesnt cancel out that effect?
sorry dont think thats very clear ^ ...
I believe that you are comparing a parallel circuit to a series circuit.
The battery is rated at a specific voltage. The voltage measures the amount of energy per coulomb of electrons. The amperage measures the number of coulombs of electrons which pass a specific point in the circuit each second. As the current flows through a light bulb, the electric energy is converted light energy.
As the current flows through the entire circuit, the voltage decreases from the voltage of the battery to 0 volts.
Let’s look at a 12 volt system with 2 bulbs with resistance of 6 ohms each.
In a parallel circuit, the current leaves the battery and comes to the junction of the 2 branches of the parallel circuit. Since the resistance of each bulb is the same, half the current flows through each bulb. Then the current flows to the other terminal of the battery. The voltage of the current flowing through each branch of the parallel circuit will decrease from 12 volt to 0 volt.
Voltage decrease = Current * Resistance
12 = Current * 6 ohms
Current = 2 amps
Each branch of the parallel circuit has 2 amps of current flowing through it. This means each bulb has 2 amps of current flowing through it.
Power = Volts * amps
Power = 12 * 2 = 24 watts
my textbook says that in parallel circuits, bulbs are brighter because the voltage isnt shared but if power is voltage x current, how comes the current dividing in a parallel circuit doesnt cancel out that effect?
sorry dont think thats very clear ^ ...
I believe that you are comparing a parallel circuit to a series circuit.
The battery is rated at a specific voltage. The voltage measures the amount of energy per coulomb of electrons. The amperage measures the number of coulombs of electrons which pass a specific point in the circuit each second. As the current flows through a light bulb, the electric energy is converted light energy.
As the current flows through the entire circuit, the voltage decreases from the voltage of the battery to 0 volts.
Let’s look at a 12 volt system with 2 bulbs with resistance of 6 ohms each.
In a parallel circuit, the current leaves the battery and comes to the junction of the 2 branches of the parallel circuit. Since the resistance of each bulb is the same, half the current flows through each bulb. Then the current flows to the other terminal of the battery. The voltage of the current flowing through each branch of the parallel circuit will decrease from 12 volt to 0 volt.
Voltage decrease = Current * Resistance
12 = Current * 6 ohms
Current = 2 amps
Each branch of the parallel circuit has 2 amps of current flowing through it. This means each bulb has 2 amps of current flowing through it.
Power = Volts * amps
Power = 12 * 2 = 24 watts
12
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