determine the frequency of a photon whose energy is 3.00*10^-19 joule
________*10^14 Hz
________*10^14 Hz
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The energy of a photon is
E = hf
where h is 6.63 x 10^-34 J*s
Therefore the frequency is f = E/h
f = (3.00 x 10^-19 J) / (6.63 x 10^-34 J*s) = 4.52 x 10^14 s^-1
E = hf
where h is 6.63 x 10^-34 J*s
Therefore the frequency is f = E/h
f = (3.00 x 10^-19 J) / (6.63 x 10^-34 J*s) = 4.52 x 10^14 s^-1