Some help on Algebra II greatly appreciated?
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Some help on Algebra II greatly appreciated?

[From: ] [author: ] [Date: 14-02-25] [Hit: ]
The polynomial is the product of those three factors. Just to give you one more hint, subtracting a negative is the same as adding. If -2 is a root, then (x - (-2)) is a factor which means (x + 2) is a factor.-Firstly,......

5. No. 3x - 12 is not a cubic, and it doesn't have -2, -4 or -3 as a zero. So it doesn't exactly fit the requirements. The solution to 3x - 12 = 0 is 3x = 12 or x = +4, which is not one of your given roots. A cubic has an x^3 in it.

If a polynomial has a root r, then it has a factor (x - r). So you can immediately write down three factors, one for each root. The polynomial is the product of those three factors.

Just to give you one more hint, subtracting a negative is the same as adding. If -2 is a root, then (x - (-2)) is a factor which means (x + 2) is a factor.

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Firstly, flabbergasted means: astounded...not what you think it means...confused !!

2. Please use the rational root theorem theorem to list all possible rational roots of the polynomial equation: x^3-x^2+7x-5=0. (Do not find the actual roots.)
possible rational roots are:
± [1, 5 ]

here is a link
http://www.purplemath.com/modules/rtnlro...

3. Find all zeros of the equation: 32x^2-144 = -x^4

set equal to zero...factor, solve...

x^4 + 32x^2 - 144 = 0
(x^2 + 36)(x^2 - 4) = (x^2 + 36)(x + 2)(x - 2) = 0
x = ± 6i or x = ± 2
check...I did

Post fewer problems at one time

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