So the question is (2b/5c)3 the 3 is little btw. Please help!
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(2b/5c)³ =
(2b)³ / (5c)³ =
8b³ / 125c³
the 8 is just 2X2X2, three times because of the small 3, and so is the 125 (5X5X5).
(2b)³ / (5c)³ =
8b³ / 125c³
the 8 is just 2X2X2, three times because of the small 3, and so is the 125 (5X5X5).
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(2b/5c)^3 can be written out as (2b)^3 / (5c)^3
So if we do this separately: 2b x 2b x 2b = 8b^3.
And now for (5c)^3: 5c x 5c x 5c = 125c^3.
So the final answer will be (8b^3) / (125c^3)
Btw the "^" means to the power of so the number following will be "little", hope this helps.
So if we do this separately: 2b x 2b x 2b = 8b^3.
And now for (5c)^3: 5c x 5c x 5c = 125c^3.
So the final answer will be (8b^3) / (125c^3)
Btw the "^" means to the power of so the number following will be "little", hope this helps.
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You have to take the cube of both the numerator and the denominator.
So it would be rewritten as
(2b)^3
----------
(5c)^3
Then you cube both the number and the variable and the final answer is
8b^3
--------
125c^3
and the ^3 just means a little 3
So it would be rewritten as
(2b)^3
----------
(5c)^3
Then you cube both the number and the variable and the final answer is
8b^3
--------
125c^3
and the ^3 just means a little 3
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(2b/5c)^3 (raised to the exponent 3)
so you can raise the numerator to 3 and the denominator to 3
so that's (2 cubed times b cubed) divided by (5 cubed times c cubed)
(8b^3)/(125c^3)
so you can raise the numerator to 3 and the denominator to 3
so that's (2 cubed times b cubed) divided by (5 cubed times c cubed)
(8b^3)/(125c^3)