Math Exponents question, please help! Grade 9 math
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Math Exponents question, please help! Grade 9 math

[From: ] [author: ] [Date: 13-11-05] [Hit: ]
hope this helps.-You have to take the cube of both the numerator and the denominator.......
So the question is (2b/5c)3 the 3 is little btw. Please help!

-
(2b/5c)³ =

(2b)³ / (5c)³ =

8b³ / 125c³

the 8 is just 2X2X2, three times because of the small 3, and so is the 125 (5X5X5).

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(2b/5c)^3 can be written out as (2b)^3 / (5c)^3

So if we do this separately: 2b x 2b x 2b = 8b^3.

And now for (5c)^3: 5c x 5c x 5c = 125c^3.

So the final answer will be (8b^3) / (125c^3)

Btw the "^" means to the power of so the number following will be "little", hope this helps.

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You have to take the cube of both the numerator and the denominator.
So it would be rewritten as
(2b)^3
----------
(5c)^3

Then you cube both the number and the variable and the final answer is

8b^3
--------
125c^3

and the ^3 just means a little 3

-
(2b/5c)^3 (raised to the exponent 3)
so you can raise the numerator to 3 and the denominator to 3
so that's (2 cubed times b cubed) divided by (5 cubed times c cubed)
(8b^3)/(125c^3)
1
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