Can someone help find the solution to x^2+x-6=-2x+4

And for x^2+4x-15=3x+5 as well . Thanks! I'd appreciate the help!

x² + 4x - 15 = 3x + 5
x² + x - 20 = 0
(x + 5)(x - 4) = 0
x = -5 and 4

x² + x - 6 = -2x + 4
x² + 3x - 10 = 0
(x + 5)(x - 2) = 0
x = -5 and 2

x^2 + x - 6 = -2x + 4, this becomes
x^2 +x +2x -6 -4 =0, then we do like terms
x^2 + 3x -10 = 0, we factor it
(x + ____) * (x - ___)=0, numbers that multiplied give you 10 and subtracted 3 (5 and 2)
(x+5) * (x-2) = 0 solve for each
x+5=0
x-2=0
you get
X1=-5 and X2=2

for the other one

x^2 + 4x - 15 = 3x + 5
same as before
x^2 +4x - 3x - 15 - 5 =0
x^2 + x - 20 = 0
(x + ____) * (x - __ ) = 0
(x + 5) * ( x - 1\4 ) = 0
x+5=0
and
x-4=0
you get
X1= - 5
X2= 4

why do you have to cheat? dont mean to be hard on you bht its true.