Ayie is 8 years older than icas. The sum of their age is 32. How old is each now?
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Let icas' age be x
age of ayie = x+8
x + (x+8) = 32
2x + 8 = 32
2x = 24
x=12
Current Ages - Ayie:20 Icas:12
age of ayie = x+8
x + (x+8) = 32
2x + 8 = 32
2x = 24
x=12
Current Ages - Ayie:20 Icas:12
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icas age =x
avie age = x+8
deir sum = 42
x+x+8=42
2x+8=42
2x=34
x=17 icas's age
ayie's age = x+8 = 7+8=15 yrs.
and ya dats how ya do it mon
avie age = x+8
deir sum = 42
x+x+8=42
2x+8=42
2x=34
x=17 icas's age
ayie's age = x+8 = 7+8=15 yrs.
and ya dats how ya do it mon
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ICAS = X YEARS
AYIE = X +8 YEARS
JUST ADD 2X + 8 = 32
2X = 24
X = 12
X+8 = 20
ANSWER ICAS = 12 YEARS AYIE = 20 YEARS
AYIE = X +8 YEARS
JUST ADD 2X + 8 = 32
2X = 24
X = 12
X+8 = 20
ANSWER ICAS = 12 YEARS AYIE = 20 YEARS
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Icas is 12. Ayie is 20. Sounds like a math text book problem from the interesting names.
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I agree with milind.