Could you explain& work out these problems for me? I really don't understand them. Click the link. i took a photo of them (: Thank you SO much!
http://www.flickr.com/photos/95873920@N07/8756071094/
http://www.flickr.com/photos/95873920@N07/8756071094/
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i'm doing it on paper for you, but for the second question you can't solve that if the only information you have is two of the sides lengths
You either need an angle as well or another side to solve for the area
http://i42.tinypic.com/2z729v9.jpg
I forgot to divide by 2 when getting the area of the triangle in the picture. The area of the triangle is just sqrt12, and the area of the hexagon is 8sqrt12 or 27.71
So for question 1, the bottom side of the triangle is 2ft since its half the length of the hexagon's bottom side. The hypotenous of the triangle is the same as the hexagon's sides, so its 8. Using pythagorean theorem, c^2 - b^2 = a^2. (4^2 - 2^2 = a^2) ...(12 = a^2) you get the other side to be sqrt12 ft long. The area of the triangle is (b x h)/2
which is 2(sqrt12) / 2 = sqrt12. 8 of these triangle make up the hexagon, so the area is 8 times the area of one triangle. The total area is 8(sqrt12), or 27.71.
For question 3, you need the middle rims area. You can get the middle rim's area by finding the area of the entire circle, then substracting the small circles area, then substracting the area of the outer rim. You can get the area of the outer rim by subtracting the area of the shaded circle from the area of the big circle.
You either need an angle as well or another side to solve for the area
http://i42.tinypic.com/2z729v9.jpg
I forgot to divide by 2 when getting the area of the triangle in the picture. The area of the triangle is just sqrt12, and the area of the hexagon is 8sqrt12 or 27.71
So for question 1, the bottom side of the triangle is 2ft since its half the length of the hexagon's bottom side. The hypotenous of the triangle is the same as the hexagon's sides, so its 8. Using pythagorean theorem, c^2 - b^2 = a^2. (4^2 - 2^2 = a^2) ...(12 = a^2) you get the other side to be sqrt12 ft long. The area of the triangle is (b x h)/2
which is 2(sqrt12) / 2 = sqrt12. 8 of these triangle make up the hexagon, so the area is 8 times the area of one triangle. The total area is 8(sqrt12), or 27.71.
For question 3, you need the middle rims area. You can get the middle rim's area by finding the area of the entire circle, then substracting the small circles area, then substracting the area of the outer rim. You can get the area of the outer rim by subtracting the area of the shaded circle from the area of the big circle.