solve the system of equations.
4x - 5y = 27
3x - 9y = 36
can you guys show me every step on how to the solve this math problem please...
4x - 5y = 27
3x - 9y = 36
can you guys show me every step on how to the solve this math problem please...
-
(4x-5y=27) x 3
(3x-9y=36) x 4
12x-15y=81
12x-36y=144
-21y=63
Y=-3
3x-9(-3)=36
3x-(-27)=36
3x=9
X=3
Y=-3
(3x-9y=36) x 4
12x-15y=81
12x-36y=144
-21y=63
Y=-3
3x-9(-3)=36
3x-(-27)=36
3x=9
X=3
Y=-3
-
You can use substitution to solve this, and so you want to get one of the variables by itself and then plug that back into the other equation.
4x = 27 + 5y
x = 27/4 + 5/4y
3(27/4 + 5/4y) - 9y = 36
81/4 + 15/4y - 9y = 36
81/4 - 21/4y = 36
-21/4y = 63/4
y=-3
Now that you have a number for y, you can plug that back into the equation.
4x - 5(-3) = 27
4x + 15 = 27
4x=12
x=3
You can then check your answer by putting that x into the other equation, and it should give you what you have for y.
3(3) - 9y =36
9 - 9y = 36
-9y = 27
y = -3
Therefore, the point of intersection is (3,-3).
4x = 27 + 5y
x = 27/4 + 5/4y
3(27/4 + 5/4y) - 9y = 36
81/4 + 15/4y - 9y = 36
81/4 - 21/4y = 36
-21/4y = 63/4
y=-3
Now that you have a number for y, you can plug that back into the equation.
4x - 5(-3) = 27
4x + 15 = 27
4x=12
x=3
You can then check your answer by putting that x into the other equation, and it should give you what you have for y.
3(3) - 9y =36
9 - 9y = 36
-9y = 27
y = -3
Therefore, the point of intersection is (3,-3).
-
4x - 5y = 27
3x - 9y =36
Take the second equation, 3x - 9y =36, this can be written as
3x = 36+9y, x = (36+9y)/3
X = 12+3y
Now substitute the above value of X in 4x - 5y = 27
4*(12+3y) - 5y = 27
48 + 12y - 5y =27
7y = 27-48, 7y = -21, y=-21/7
y = -3;
Now substitute y=-3 in x=12+3y;
x = 12 +(3*-3)
x = 12+(-9)
X= 12-9
X= 3
hence the solution of the pair of equations is X=3 Y= - 3
3x - 9y =36
Take the second equation, 3x - 9y =36, this can be written as
3x = 36+9y, x = (36+9y)/3
X = 12+3y
Now substitute the above value of X in 4x - 5y = 27
4*(12+3y) - 5y = 27
48 + 12y - 5y =27
7y = 27-48, 7y = -21, y=-21/7
y = -3;
Now substitute y=-3 in x=12+3y;
x = 12 +(3*-3)
x = 12+(-9)
X= 12-9
X= 3
hence the solution of the pair of equations is X=3 Y= - 3
-
multiply the top equation by 3 and the bottom equation by 4 .
12x - 15y = 81
12x - 36y = 144 Now SUBTRACT the TWO equations by changing the second equations's signs to the their opposites then adding.
12x - 15y = 81
-12x -+36y = -144
21y = -63
y = -3 can you find x now?
12x - 15y = 81
12x - 36y = 144 Now SUBTRACT the TWO equations by changing the second equations's signs to the their opposites then adding.
12x - 15y = 81
-12x -+36y = -144
21y = -63
y = -3 can you find x now?
-
4x - 5y = 27
3x - 9y = 36
Multiply second equation by 4/3
4x - 5y = 27
4x - 12y = 48
Subtract
7y = -21
y = -3
Plug y back into one of the earlier equations and solve for x
4x - 5y = 27
4x - 5(-3) = 27
x = 3
3x - 9y = 36
Multiply second equation by 4/3
4x - 5y = 27
4x - 12y = 48
Subtract
7y = -21
y = -3
Plug y back into one of the earlier equations and solve for x
4x - 5y = 27
4x - 5(-3) = 27
x = 3
-
4x - 5y = 27 ------- (1)
3x - 9y = 36 ------- (2)
(1) × 3 and (2) × 4
12x - 15y = 81 ------- (3)
12x - 36y = 144 ------- (4)
(3) – (4)
21y = – 63
y = – 3
using
4x - 5y = 27 ------- (1)
4x + 15 = 27
4x = 12
x = 3
----
3x - 9y = 36 ------- (2)
(1) × 3 and (2) × 4
12x - 15y = 81 ------- (3)
12x - 36y = 144 ------- (4)
(3) – (4)
21y = – 63
y = – 3
using
4x - 5y = 27 ------- (1)
4x + 15 = 27
4x = 12
x = 3
----
-
4x - 5y = 27 -(1)
3x - 9y = 36 -(2)
from (2), x - 3y = 12 -(3)
from (3), 4x - 12y = 48 -(4)
(4) - (1), get y= -3
put y= -3 into (3) and get x=3
Answer is: x=3 and y= -3
3x - 9y = 36 -(2)
from (2), x - 3y = 12 -(3)
from (3), 4x - 12y = 48 -(4)
(4) - (1), get y= -3
put y= -3 into (3) and get x=3
Answer is: x=3 and y= -3