Prove that (tan x+cot x/csc^2x)=tan x
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Prove that (tan x+cot x/csc^2x)=tan x

[From: ] [author: ] [Date: 13-04-21] [Hit: ]
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Needing help proving this. Can't seem to get it right :\ Any help will be much appreciated.

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This took me a while, but that was because I think you meant (tan+cot)/csc^2.

Dividing by csc^2 is the same as multiplying by sin^2 so you have sin^2(tan+cot)=tan

tan = sin/cos and cot = cos/sin

Make the partial fraction a single fraction: (sin^2 + cos^2)/(sincos)
The top simplifies to 1 and the bottom can cancel with one of the sines in sin^2

That leaves you with sin/cos=tan
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