Trigonometry Problem Help Please
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Trigonometry Problem Help Please

[From: ] [author: ] [Date: 13-02-16] [Hit: ]
......
To Prove:
tanθ + secθ = 1+sinθ/cosθ

and

cos²(90-θ)/1+cosθ = 1-cosθ

Please don't just give the answers, I actually don't know how to work it out.
Please explain.
Much appreciated.

-
tanθ=sinθ/cosθ and secθ =1/cosθ
now tanθ + secθ =sinθ/cosθ +1/cosθ
it implies sinθ+1/cosθ hence proved
and
cos²(90-θ)=sin²θ
so cos²(90-θ)/1+cosθ = sin²θ/1+cosθ
because sin²θ+cos²θ=1 it implies sin²θ=1-cos²θ
now 1-cos²θ/1+cosθ
(1-cosθ)(1+cosθ)/1+cosθ=1-cosθ hence proved
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