Solve it algebraically using the quadratic formula. Round to 2 decimal places
y=-x^2+2x+9
y=-5x^2+10x+12
My answer came to the conclusion to having -4x^2+8x+3=0
(-2x ? ) (2x ? ) there's no number that can multiple and add to 3 and 8? So i'm having a little trouble finding the solution
y=-x^2+2x+9
y=-5x^2+10x+12
My answer came to the conclusion to having -4x^2+8x+3=0
(-2x ? ) (2x ? ) there's no number that can multiple and add to 3 and 8? So i'm having a little trouble finding the solution
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Your conclusion is perfectly fine, and you are correct that there is no way to factorise your equation mentally. In situations where you can't factorise your quadratic you need to use the quadratic formula:
-b+-sqrt(b^2-4ac)/2a
I know that's a bit messy but I would hope you know what I'm talking about anyway.
Plugging your values into said formula results in 2 solutions:
x = (2+-sqrt(7))/2
-b+-sqrt(b^2-4ac)/2a
I know that's a bit messy but I would hope you know what I'm talking about anyway.
Plugging your values into said formula results in 2 solutions:
x = (2+-sqrt(7))/2