Working out too please :)
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One could factor out a "5x" to get
(5x)(x + 2y + 3xy)
One could factor out "x" to get (x)(5x + 10y + 15xy) & then factor out "x" from (5x + 15xy) that's within the parenthesis to get
(x)(x(15y + 5) + 10y)
Or you could factor out "5" from the last 1 & get
5x(x(3y + 1) +2y)
One could keep the 5x^2 term out in front & factor the second 2 terms to get
5x^2 + (15x + 10)xy
One could Keep the middle term, & factor the 2 outside terms to get
10xy + x^2(5+15y)
(5x)(x + 2y + 3xy)
One could factor out "x" to get (x)(5x + 10y + 15xy) & then factor out "x" from (5x + 15xy) that's within the parenthesis to get
(x)(x(15y + 5) + 10y)
Or you could factor out "5" from the last 1 & get
5x(x(3y + 1) +2y)
One could keep the 5x^2 term out in front & factor the second 2 terms to get
5x^2 + (15x + 10)xy
One could Keep the middle term, & factor the 2 outside terms to get
10xy + x^2(5+15y)
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5x(x+2y+3xy)