through:(-2,0), parallel to y=-1/2x-2
Write the standard form of the equation of the line described.
Help please i have a test and i dont understand these types of questions
Write the standard form of the equation of the line described.
Help please i have a test and i dont understand these types of questions
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y = ax + b to be parallel a = -1/2
through (-2,0) => 0 = -1/2 *( -2) + b
0 = 1 + b
b = -1
then y = -1/2x -1
through (-2,0) => 0 = -1/2 *( -2) + b
0 = 1 + b
b = -1
then y = -1/2x -1
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The given line has gradient = -1/2, and any line parallel to this one will have the same gradient. The most useful form of the equation of a line (whish I assume you've met) is y-b = m(x-a), where m is the gradient, and the fixed point is (a,b), in this case (-2,0). Plug in the values and you're finished.