Hi
i don't know how to solve this question please help
A point P lies on the graph of the function y = x2, 0
please help
i don't know how to solve this question please help
A point P lies on the graph of the function y = x2, 0
please help
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The point (x, x^2) determines the width that the height of the rectangle.
width = 2 - x
height = x^2
so the are of the rectangle is
A = width * height = 2x^2 - x^3
A' = 4x - 3x^2
Setting A' = 0 and solving for x, we get
4x - 3x^2 = 0
x(4 - 3x) = 0
x = 0 or x = 4/3
we reject x = 0.
So x = 4/3
The largest possible area of the rectangle is
2(4/3)^2 - (4/3)^3 = 32/27
width = 2 - x
height = x^2
so the are of the rectangle is
A = width * height = 2x^2 - x^3
A' = 4x - 3x^2
Setting A' = 0 and solving for x, we get
4x - 3x^2 = 0
x(4 - 3x) = 0
x = 0 or x = 4/3
we reject x = 0.
So x = 4/3
The largest possible area of the rectangle is
2(4/3)^2 - (4/3)^3 = 32/27