Cal Related Rates problem
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Cal Related Rates problem

[From: ] [author: ] [Date: 12-11-01] [Hit: ]
9.dh/dt=-3/2=-1.......
A 15 ft ladder leans against a wall. The bottom of the ladder is 3 ft from the wall at time t=0 and slides away from the wall at a rate of 2 {ft/sec}.

Find the velocity of the top of the ladder at time t=3.

The velocity of ladder at time t = 3 is

-
dx/dt=2 ft/s

dy/dt l t=3 sec , x=3+6 , x=9


x and h are func. of t

so x(t)^2+h(t)^2=15^2

implicit diff. with respect to t is

2xdx/dt+2hdh/dt=0

2.9.2+ 2√(15^2-9^2)*dh/dt=0

dh/dt=-18/√(15^2-9^2) ft/sec

dh/dt=-3/2=-1.5 ft/sec
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