Let the velocity of a particle be v(t) =i+tj and let its position when t=0 be r(0)=j+2k Find position when t=0
Please show and describe how to do this. The answer key says 2i+3j+2k
Please show and describe how to do this. The answer key says 2i+3j+2k
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d(r(t))/dt = v(t) = i + jt
r(t) = (t + m)i + (t^2/2 + n)j + pk, m,n,p constants
r(0) = mi + nj + pk = j + 2k
thus m = 0, n = 1, p = 2
r(t) = ti + (t^2/2 + 1)j + 2k
r(2) = 2i + 3j + 2k
r(t) = (t + m)i + (t^2/2 + n)j + pk, m,n,p constants
r(0) = mi + nj + pk = j + 2k
thus m = 0, n = 1, p = 2
r(t) = ti + (t^2/2 + 1)j + 2k
r(2) = 2i + 3j + 2k
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You need to be more clear.
You are stating the position at t = 0 is r(0) = j + 2k and then you are asking to find the position when t = 0 ?!!!
You are stating the position at t = 0 is r(0) = j + 2k and then you are asking to find the position when t = 0 ?!!!