If it is, must f(1)=5? Can we conclude anything about the values of f at x=1? Explain.
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Let f(x)=5 everywhere except x=1, and let f(1) be undefined. Then lim x->1 is 5 but f(1) is undefined.
Let f(x)=5 everywhere except x=1, and let f(1)=0. Then still lim x->1 is 5, since you can always find a neighborhood of 1 where f is as close as you like to 5.
Let f(x)=5 everywhere except x=1, and let f(1)=0. Then still lim x->1 is 5, since you can always find a neighborhood of 1 where f is as close as you like to 5.
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Must f be defined at 1... no.
If it must, f(1) = 5... no.
You can't conclude anything about f(1), no.
If it must, f(1) = 5... no.
You can't conclude anything about f(1), no.