∫4
(x/2)dx
∫0
(x/2)dx
∫0
-
This integral represents the area between y = x/2 and the x-axis for x in [0, 4].
Sketching this yields a triangular region (above the x-axis) with base length 4 and height 4/2 = 2.
Hence, the area (integral) equals (1/2) * 4 * 2 = 4.
I hope this helps!
Sketching this yields a triangular region (above the x-axis) with base length 4 and height 4/2 = 2.
Hence, the area (integral) equals (1/2) * 4 * 2 = 4.
I hope this helps!