1.02ⁿ=3 .......What is the value of n

1.02ⁿ = 3

Log 1.02ⁿ = Log 3
n Log 1.02 = Log 3
n = Log 3 / Log 1.02 = 55.48

Hope that helps and good luck :)

Exploit properties of logs. Take the log of both sides(it doesn't matter what the base is so long as you're consistent). log(1.02^n) = log 3. Exploit log property: log a^b = bloga so
nlog1.02=log3 and therefore
n= log3/log1.02

1.02^(n) = 3

Ln[1.02^(n)] = Ln(3)

n.Ln(1.02) = Ln(3)

n = Ln(3)/Ln(1.02)

n ≈ 55.4781

log1.02ⁿ = log3
nlog 1.02 = log 3
n= (log 3)/(log 1.02)