Please answer this very difficult math problem......

7 years before john's age was equal to 7 times the age of smith...while after 3 years john's age will be equal to 3 times
the age of smith....find their ages....the answer is 42 and 12

Let the current age of smith be x and john be y

Seven years ago, john's age = y - 7 and smith's age = x - 7
According to question
(y - 7) = 7(x - 7)

Three years later, john's age = y + 3 and smith's age = x + 3
According to question
(y + 3) = 3(x + 3)

Solving the two eaquations we get x = 12 and y = 42

john age = y - 7 and smith age = x - 7
equation is
(y - 7) = 7(x - 7)

after 3 years john's age = y + 3 and smith's age = x + 3
the equation will be
(y + 3) = 3(x + 3)

solve it and you will get x = 12 and y = 42

Let the current ages be j & s.

Then j-7 = 7(s-7) and j+3 =3(s+3)

All you need to do now is solve this two simultaneous equations either algebriaically or graphically.

7x7 AGE OF SMITH I THINK :O SO HARD LOL