Factor x^2+11x+24 please

1.) Find two factors of 24 that add up to 8. That would be 8 & 3.

2.) Now put it together. (x+3) (x+8).

You can check the answer by using the distributive property.

The answer is (x+3)(x+8).

The trick to factoring quadratic polynomials, that don't have a leading coefficient greater than one, is to simply find two numbers that will multiply to equal the constant coefficient and add to equal the linear coefficient. From there you simply put it in a nomial form. In this case 3*8=24 and 3+8=11. So the answer is (x+3)(x+8).

Hopefully this helped. Have a nice day.

Factors of 24 that add up to 11: 3 & 8

(x + 3)(x + 8)

I hope this information was very helpful.

(x+3)(x+8)

FOIL (First, outside, inside, last)

x*x = x^2
x*8 = 8x
x*3 = 3x
(3x+8x=11x)
3*8 = 24

x^2 + 11x + 24

(x+3)(x+8)

(x+8)(x+3)

x^2+11x+24

=(x+8)(x+3)

X equals -3 and -8

Since the x^2 coefficient is 1, we need to find two numbers that multiply to the constant term (24) and add to make the coefficient of x (8). To see why, note that the factorization will take the form:
x^2 + 11x + 24 = (x + a)(x + b),

for some a and b. If you expand the right side, you will get:
x^2 + 11x + 24 = x^2 + (a + b)x + ab.

Then, a and b satisfy the following system:
a + b = 11 and ab = 24;

in other words, a and b are two numbers that add to 11 and multiply to make 24, which is what I said we needed to do above. In general, you can factor a quadratic that has a 1 as a coefficient on its squared term by finding two numbers that add to make the linear coefficient that multiply to make the constant. In this case, these two numbers are 8 and 3 (since 8 + 3 = 11 and 8*3 = 24), so we stick them where a and b are to get:
x^2 + 11x + 24 = (x + 8)(x + 3).

I hope this helps!