(2+x)squared(1-x)cube
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(2+x)squared(1-x)cube

[From: ] [author: ] [Date: 12-07-05] [Hit: ]
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Derivative of a Function - Increment Method Subject: Differential Calculus

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(2+x)²(1-x)³ = uv where

u = (2+x)² and v = (1-x)³
u' = 2(2+x) and v' = -3(1-x)²

The derivative (using the product formula) is

u'v + uv'
= 2(2+x)(1-x)³ + (2+x)²(-3(1-x)²)

Take out the common factor (2+x)(1-x)² to get
(2+x)(1-x)²[2(1-x) - 3(2+x)]
= (2+x)(1-x)²(-4-5x)
= -(2+x)(1-x)²(4+5x)

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you need the derivative? that would be (2+x)(1-x)^3 + (2+x)^2*-3(1-x)^2
(that's if your original problem was being multiplied together which i think is what you were trying to show)
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keywords: squared,cube,(2+x)squared(1-x)cube
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