A cube has all sides equal to x. Let x change with respect to t such that x(t) = 3t – 2. What is the formula for the rate of change of the volume of the cube?
=V(t) is V’(t) = 3(3t – 2)^2
=V(t) is V’(t) = 27(3t – 2)^2
=V(t) is V’(t) = 9(3t – 2)^2
=V(t) is V’(t) = -9(3t – 2)^2
=V(t) is V’(t) = 3(3t – 2)^2
=V(t) is V’(t) = 27(3t – 2)^2
=V(t) is V’(t) = 9(3t – 2)^2
=V(t) is V’(t) = -9(3t – 2)^2
-
x = 3t - 2 ... so dx/dt = 3
V = x^3 ... so dV/dx = 3x^2
dV/dt = dV/dx * dx/dt
= 3x^2 * 3
= 9x^2
= 9(3t - 2)^2
V = x^3 ... so dV/dx = 3x^2
dV/dt = dV/dx * dx/dt
= 3x^2 * 3
= 9x^2
= 9(3t - 2)^2