But since the first two terms count for 20% each,and the third(final term)counts for 60%. I got 38% in the first term,48% second term,so how much do i need to pass the third one? And are you sure about your answer? Our pass mark is 60%
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0.2x38 + 0.2x48 = 0.2x(38+48) = 86x0.2 = 17.2
60 - 17.2 = 42.8
42.8/0.6 = 71.333r → 72
You need to get a 72%
Am I sure about my answer? I am sure that 38%x20% + 48%x20% + 72%x60% > 60%
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But given that you are doing so poorly, I suggest that you exert all possible effort to study, since otherwise it isn't very hopeful.
Review, do problems, review, answer questions. Practice.
60 - 17.2 = 42.8
42.8/0.6 = 71.333r → 72
You need to get a 72%
Am I sure about my answer? I am sure that 38%x20% + 48%x20% + 72%x60% > 60%
---
But given that you are doing so poorly, I suggest that you exert all possible effort to study, since otherwise it isn't very hopeful.
Review, do problems, review, answer questions. Practice.