Find the x and y intercept of f(x)=1-(3/(x^2))

can you show me how to find the answer

to find x intercept you put f(x) =0
1 - 3/x^2 = 0
(x^2 - 3) / x^2 = 0
x^2 - 3 = 0
x = + and - sqrt(3)

the y intercept should be found putting x = 0 in the equation f(x)
but we cannot compute 1 - 3/0 !!!
so there is no y intercept

To determine x intercept, we'll put y = f(x) = 0.

But f(x) = x^2-3x+1 => x^2-3x+1 = 0

We'll apply quadratic formula:

x1 = [3+sqrt(9 - 4)]/2

x1 = (3+sqrt5)/2

x2 = (3-sqrt5)/2


To determine y intercepts, we'll cancel the x coordinate.

f(0) = 0^2 - 3*0 + 1

f(0) = 1

The y intercept is (0 , 1).

The x intercepts are ((3+sqrt5)/2 , 0) and ((3-sqrt5)/2) , 0) and the y intercept is (0 , 1).

jrb