Consider this quadratic function. Reduce all fractions to lowest terms.

Graph this parabola by identifying 2 points on the parabola, other than the vertex and the point if any where the parabola crosses the x axis.
POINT A: (?,?)
POINT B:(?,?)
y=x^2+4x+10

The parabola cross the x-axis at the points y=0

x^2+4x+10=0
so factorise, i can't see any integers so use the quadratic formuale

x=-b +/-(b^2-4ac)^1/2 / 2a where ax^2+bx+c=0,
so a=1, b=4, c=10x=-4 +/- (16-4.1.10)^1/2 / 2(1)

have you written this correctly as you have complex roots tot his (-24)^1/2 ??

EDIT
Ok, BUT YOU'VE COMPLEX ROOTS! lol..

x= -4 +/- (-24)^1/2 / 4, so
x=-1+6i and x=-1-6i (where i=(-1)^1/2

so you have an argand diagram to see these roots!?

If you look at x=0, y=10, let x=-2 (this is it's minimum value) then y= 6 !

So, no REAL roots exist for this parabola.
I'm sorry I can't be any more help, sorry.