0.015=(-0.0592/2) [log (x/0.1)]
i have no idea how to get x alone, please help!
i have no idea how to get x alone, please help!
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One of the properties of logs is that you can split them u if they are multiplied or divided. So you can write it out like this
0.015=(-0.0592/2) [log (x) - log (0.1)]
So now you divide both sides by -0.0592/2 and subtract the log (0.1) to get:
[(0.015)/(-0.0592/2)] - log (0.1) = log x
And log is the same as log base 10 so:
x = 10 ^[(0.015)/(-0.0592/2) - log (0.1)]
0.015=(-0.0592/2) [log (x) - log (0.1)]
So now you divide both sides by -0.0592/2 and subtract the log (0.1) to get:
[(0.015)/(-0.0592/2)] - log (0.1) = log x
And log is the same as log base 10 so:
x = 10 ^[(0.015)/(-0.0592/2) - log (0.1)]