Ok... so how do you get a trinomial from an equation with 3 parenthesizes?
Ex: (x-y) (x+y) - (-x)
I am on Global compass' math lab.
It doesn't explain how it did that and I can't figure it out.
The real equation is: (x-4) (x-1) - (-10x) / (x-1) (x-1) + (x+1)x.
Please don't answer the real one.
I just need to know how to deal with it.
Thanks!
Ex: (x-y) (x+y) - (-x)
I am on Global compass' math lab.
It doesn't explain how it did that and I can't figure it out.
The real equation is: (x-4) (x-1) - (-10x) / (x-1) (x-1) + (x+1)x.
Please don't answer the real one.
I just need to know how to deal with it.
Thanks!
-
Order of Operations PEMDAS
P parentheses
E exponents
MD multiplication and division
AS addition and subtraction
Note that the last parenthesis (-x) is subtracted from the others. Addition and subtraction are like stop signs. You need to do the operations between the addition and subtraction symbols first. Then come back and address them later.
Here, the stuff in the parentheses can't be simplified further. There are no exponents, so multiplication is next
FOIL out the two parentheses.
You get (x-y) (x+y) = x^2 - y^2
So = (x-y) (x+y) - (-x) = x^2 - y^2 - (-x)
(x-y) (x+y) - (-x) = x^2 - x - y^2
I hope this helps
P parentheses
E exponents
MD multiplication and division
AS addition and subtraction
Note that the last parenthesis (-x) is subtracted from the others. Addition and subtraction are like stop signs. You need to do the operations between the addition and subtraction symbols first. Then come back and address them later.
Here, the stuff in the parentheses can't be simplified further. There are no exponents, so multiplication is next
FOIL out the two parentheses.
You get (x-y) (x+y) = x^2 - y^2
So = (x-y) (x+y) - (-x) = x^2 - y^2 - (-x)
(x-y) (x+y) - (-x) = x^2 - x - y^2
I hope this helps