Differentiate y= 10^11x

Show work, thanks!

Given:
d/dx [10^(11x)]

Let u = 11x.

Via the Chain rule:
d/dx [10^u] = u' d/du [10^u] = 11(10^u)ln(10) = 11*10^(11x)ln(10)

You're unclear; If x is the base and 10^11 is the multiple, then duhh the answer is 10^11

but if x is in the power:

g(x)=10^(11x)

log g(x) = 11x => differentiate both sides

(d g(x) / dx) * (log e / g(x)) = 11

d g(x) / dx = 11.(10)^(11x).ln(10)

y = 10^11x
talking ln both sides:
ln(y) = ln(10^11x)
ln(y) = 11x * ln10
now differentiating both sides with respect to 'x'

d/dx(ln(y)) = d/dx(11x * ln10)
1/y * dy/dx = 11ln10
dy/dx = 11yln10
dy/dx = 11*(10^11x)*ln(10)
= ANSWER

= (10^11x)ln10*11x
= (10^11x)ln10*11*d/dx(x)
= 11 * 10^(11x)ln(10)

lny = 11xln10
y'/y = 11ln10
So, y' = 10^11x (11ln10)