How do i solve this polynomial

(n+2)(n^2+5n-3)

n(n^2+5n-3) +2(n^2+5n-3)
=n^3+5n^2-3n+2n^2+10n-6
=n^3+5n^2+2n^2+10n-3n-6
=n^3+7n^2+7n-6

Since the polynomial is already factored, all you need to do is set it equal to zero and solve for the roots:
(n+2)(n^2+5n-3) = 0

In this case, if either the first term or the second term equals zero, then the entire equation is zero. So, let n+2 = 0 and n^2+5n-3 = 0.

In the first case, n = -2.
In the second, use the quadratic formula:
n = (-5 + sqrt(25-4*-3))/2 or (-5 - sqrt(25-4*-3))/2
(This is an irrational number, so it's most accurate to leave n as it is.)

The right side of the polynomial is multiplied by each term inside the second parentheses. I'm not sure what the "^" means, so I'm going to show you an example:

If the polynomial is: (2a+b) (c+d) This is what you would do:

= 2ac + 2ad + bc + bd

What I did was:

1. First I took "2a" and multiplied it by "c", and then "d". This is where the "2ac + 2ad" came from.
2. Then I took "b" and multiplied it by "c" and the "d". This is where the "bc" and "bd" came from.

~*~*~*~

Nevermind, I remembered what the "^" is. So here's the solution:

n^3 + 5n^2 - 3n + 2n^2 +10n - 6

you would have to simplify and this is what it would look like:

n^3 + 7n^2 + 7n - 6