How to solve sin(xy)= x^2, then dy/dx=
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How to solve sin(xy)= x^2, then dy/dx=

[From: ] [author: ] [Date: 12-04-17] [Hit: ]
thank you.in this case u=xy,divide both sides by cos(xy),you would get choice E.......
A. 2x sec(xy)
B. sec(xy)/x^2
C. 2x sec(xy)- y
D. 2x sec(xy)/ y
E. 2x sec(xy) - y/ x
Please how u got the answer nd Ur work, it will really help, thank you.

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derivative of sin(u)=cos(u)(u')
in this case u=xy, so u'= 1(y) + x(dy/dx) -- remember thats a product rule for xy
so the derivative is cos(xy)(y+x(dy/dx)=2x -- (the derivative of x^2)

now to isolate dy/dx:
divide both sides by cos(xy), so the right side becomes 2x(sec(xy))
subtract the y and divide the whole thing by x
you would get choice E.
im assuming in the problwm at least that the x at the end of the choice is under the whole beginning expression
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