I have tried to answer this so many times, plus my friend who's basically a math genius said that it is impossible. But it's on my math homework and I need to hand it in tomorrow. If someone can help me, I'd be so grateful! Thank you!
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sin A/ 18 = sin 77 / 8
sin A = 18 sin 77 / 8 = 9 sin 77 / 4
A = sin^-1 [ 9 sin 77 / 4}
= sin^-1 (2.19)
It has no answer because the value of sin^-1 must be in the interval [-1,1]
sin A = 18 sin 77 / 8 = 9 sin 77 / 4
A = sin^-1 [ 9 sin 77 / 4}
= sin^-1 (2.19)
It has no answer because the value of sin^-1 must be in the interval [-1,1]
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A = 170.97
C = 242.54
c = 154
c is the easiest to find, just subtract the other angles from 180 to obtain it:
180 - 18 - 8 = 154
then to find the sides, use the law of sines:
A / sin(a) = B / sin(b) = C / sin(c)
we know both B and b, so that is easy to keep the same. plug in the known a and c, and solve for A and C by multiplying sin(a) and sin(c) respectively to B / sin(b)
A = 77 / sin(8) * sin(18) = 170.97
C = 77 / sin(8) * sin(154) = 242.54
C = 242.54
c = 154
c is the easiest to find, just subtract the other angles from 180 to obtain it:
180 - 18 - 8 = 154
then to find the sides, use the law of sines:
A / sin(a) = B / sin(b) = C / sin(c)
we know both B and b, so that is easy to keep the same. plug in the known a and c, and solve for A and C by multiplying sin(a) and sin(c) respectively to B / sin(b)
A = 77 / sin(8) * sin(18) = 170.97
C = 77 / sin(8) * sin(154) = 242.54
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It is impossible. The side b is too short. Just answer it "undefinite."