Solve this square root problem

Solve: square root of x+9 = square root of 3 + square root of x

sqrt(x + 9) = sqrt(3) + sqrt(x)

Let's first square both sides to get rid of the square roots:

sqrt(x+9)^2 = (sqrt3 + sqrtx)^2

x + 9 = 3 + 2sqrt3x + x

6 = 2sqrt3x

3 = sqrt3x

square both sides again

3x = 9

x = 3

square both sides to get:

x + 9 = x + 2sqrt3 + 3 rearrange to get

6 = 2sqrt 3 square both sides again

36 = 4(3x) solve for x

x = 3

Your question is un-clear...but introducing exponent 2 on all terms will work surely...than transpoese everytjing to one side.

sqrt(x + 9) = sqrt(3) + sqrt(x)
x + 9 = [sqrt(3) + sqrt(x)]^2 = x + 3 + 2sqrt(3x)
2 sqrt(3x) = 6
sqrt(3x) = 3
3x = 3^2 = 9
x = 3

x = 3