Can you factor this problem

Y^2 +y -12=0

Thanks

(y+4)(y-3)=0

the number in front of the second Y(which is 1 in this case) is the sum of the two numbers(+4 and -3).

and the constant(-12) is the product of the two numbers.

Y^2 +y -12=0
y^2+4y-3y-12 = 0
y(y+4)-3(y+4) = 0
(y+4) (y-3) = 0