Hey, I am trying to solve this system:
x^2=4y^2
x=2y+1
I went to a website and they showed me how to solve them using substitution but no matter how i solve it it always leads me to an identity or a false statement like 1/4=0 and i can't solve for either x or y. can someone show me a method or technique to solve it? I am more worried about the way to solve it i already know the result,
x^2=4y^2
x=2y+1
I went to a website and they showed me how to solve them using substitution but no matter how i solve it it always leads me to an identity or a false statement like 1/4=0 and i can't solve for either x or y. can someone show me a method or technique to solve it? I am more worried about the way to solve it i already know the result,
-
What u have to do here is substitute the value of x from 2nd eqn into the first one..So we get the result
(2y+1)^2= 4y^2
4y^2+1+4y=4y^2
1+4y=0
y=-1/4
Please tell me whether in the first eqn, 4y is whole raised to power 2 or is it just y ^2?
In that case, (2y+1)^2=16y^2
4y^2 +4y+1=16y^2
12y^2-4y-1=0
Using quadratic eqn, we get y=-1/3 or y=1/2
(2y+1)^2= 4y^2
4y^2+1+4y=4y^2
1+4y=0
y=-1/4
Please tell me whether in the first eqn, 4y is whole raised to power 2 or is it just y ^2?
In that case, (2y+1)^2=16y^2
4y^2 +4y+1=16y^2
12y^2-4y-1=0
Using quadratic eqn, we get y=-1/3 or y=1/2