Let A , B ,C be the vertices of an equilateral triangle. and let D,E be the points on the side AB such that segments AD , DE and EB each have length 1 unit .
Then tan CDE equals to :
A . 3√2
B. 2√3'
C. 3√3
D. 3√3 / 2
Then tan CDE equals to :
A . 3√2
B. 2√3'
C. 3√3
D. 3√3 / 2
-
C